Should elections have an iq test so dumb people can't vote?

The second case is 50/50 whether you picked from the first box or second box.

The question is really about the probability of which box you just picked from.

>AND THE PROBABILITY OF PICKING A GOLDEN BALL FROM A BOX WITH 2 GOLDEN BALL IS 100%
Clearly you don't understand that this is looking at the problem in a different way than the original question, so I reworded it for your pedantic ass

You have already picked a golden ball. I am talking about the probability of which box you just pulled that ball from.

>SO THE NEXT ONE WILL BE A GOLDEN ONE FOR SURE SINCE BOTH BOXES HAVE 2 GOLDEN BALLS
Clearly you just don't have the capability to look at the problem in any other way.

>RETARD
People falling for obvious trolls is funny.

>No argument
HOW I CAN BE 50% AND 50%
IF I CAN ONLY PICKING GOLDEN BALLS?

HOW?
HOW I CAN PICK A SILVER ONE?

HOW I CAN PICK A SILVER BALL?

HOW I CAN PICK A SILVER BALL FROM 2 BOXES WITH JUST GOLDEN BALLS?

NO SENSE

no wonder your country created trannies.

when you call this shit logic

YEAP
being smart mean calling a golden ball silver?

tranny logic

>no argument
to reddit now

But there are three balls left after the first pick: two gold and one silver. How is that 50/50? Are you saying that if you pick a card from a deck, the chances are 50/50 for it to be the ace of spades: it either is ace if spades or it isn't?

> three balls
ONLY 2
THE 3RD BOX IS ELIMIANTED SINCE LACK OF GOLDEN BOX

O.K., I see. You're a fucking IQ 68 retard.

You are picking out BALLS, not BOXES, you fucking inbred nagger.

You can't even speak English. This is fucking priceless. Can you produce a coherent sentence in Italian? We can try and translate it with Google Translate then.

You understand no math nor English. Double retarded Italian nagger. You are the naggers of Europe. Just slightly fairer than the naggers of Malta, but you're pretty close there.

And the probability that the ball you just picked came from box 1 or 2 is influenced by the frequency of gold balls in those boxes.

Here, for anyone arguing for 50/50, simply point out where my code is wrong. It shows approximately 33.33%.

Oh okay, now simply express that in code.

Wow, so smart. It should be easy for you you write Python, right?

Oh, my bad, I thought I was picking a good prototyping and math language but I guess I was wrong. My bad. I rewrote in C, which was the first language I ever learned, just for you. You're able to fix it now, right?

>box 3 do not exist
Fine, box 3 does not exist

2 boxes
G G
G S

You pick a random ball out of those and it is gold. You either chose
1) Box 1 Ball 1
2) Box 1 Ball 2
3) Box 2 Ball 1

What are the odds the other ball in that same box is gold?
1) 100%
2) 100%
3) 0%

1/3 + 1/3 + 0/3 = 2/3rds

>BOX 1 BALL 1
>BOX 1 BALL 2
>ARE THE SAME FUCKING CASES
And there we have the problem here and why you fucktards can't figure it out
You don't understand English.

There are 3 gold balls, when you draw the first ball imagine that there is an equal chance of that ball being any of the 3 gold balls. Work out the odds from there.

Imagine the first box has an infinity of gold balls and the second box has a near infinity of gray balls (except 1 gold ball).
Explain how the situation is not a 50/50 anyway if the first pick being gold is a precondition.

There could be an infinity of golden balls inside the first one and a near infinity of the gray balls inside the second and it still wouldnt change the probability.

Get it?
You pick the SET(box) of events. Once the box is chosen and the precondition (the pick of gold) is met you need to keep drawing from it.
The precondition makes it a 50/50. Even if it's one in a million to meet it.

FUCKING LOL
bitches about english?

YOU PICK A GOLDEN BALL
WHAT IS THE DIFFERENCE IF IS 1 OR 2?

THE DIFFERENCE IS IN THE BOX YOU TAKE IT

TARD

Don't get so upset with retards lmao.

>There could be an infinity of golden balls inside the first one and a near infinity of the gray balls inside the second and it still wouldnt change the probability.
This is your brain on retardation

You pick between the boxes einstein.
You dont pick one of the infinite balls.
YOU PICK ONE OF 3 BOXES
Once you pick a box you are forced to keep drawing from it.

Add a hundred gold balls to the first box. That will ensure you always pick the first box of three according to your retarded logic.
I guess the universe will guide your hand towards it fucking kek.

Yes but that’s a different situation, because real life doesn’t have the set initial conditions that a hypothetical problem can have.

>starts by picking from box 2
>can only pick from same box
>doesn't know he has box 2
>"Hmmmm today I will say I have 2/3rds odds because the other box can provide me two golds"
>pulls silver like a nagger

What part of
>Can only pick from the same box
Do you not get?
Detach yourself immediately from the concept that you have any choice apart from your selected box.
You've already narrowed down that only two boxes have golds. Two options - remember that.
You now have to deduce what your odds are. If you pull the gold from the box, you can either pull a gold from the 1 box, or a silver from the 2 box. By this deduction, it is 50%.
Trying to add the odds from other boxes when their total sums have zero relevance is why you end up with 2/3rds.
It's 50%. Eat shit, brainlet.

>Consider moving to a real nation with a future?
I appreciate the suggestion, but I'm fine where I live. If I lived with these literal apes, I would have moved already.
Also there's the prospect of nuclear armageddon on the horizon, so I'm just waiting to see whether it's all posturing or a potential reality, and I would rather be as far away from the theoretical danger zones.
So I WILL say that with that in mind, I'm quite happy where I am.

Good luck to you, brother

This looks correct. So is the answer 1/3?

BOX 1 AND BOX 2
the answare is 50% and 50%

box 3 is irrelecant

Change the word "gold" for 1, 2 and 3. and silver for 4, 5 and 6. Your first ball is 1, 2 OR 3 (gold), w hat are the chances your next ball from the same box is also 1, 2 OR 3 (gold)?
If you picked 1, the next one is 2 (gold)
If you picked 2, the next one is 1 (gold)
If you picked 3, the next one is 4 (silver)
Gold 2/3, Silver 1/3
I fucking hate you dumb amerimutts, no wonder China is beating the shit out of your country

1 AND 2 AS FIRST PICK

IS EQUAL
A GOLD BALL FROM BOX1
YOU ARE INFLATUATION THE RESULT

IS 50%

TAKE WHICHEVER BALL FROM BOX 1 DO NOT CHANGE THE PREMISE

YOU TAKE A GOLD BALL
IS IRRELEVAN WHICH BALL IS BUT IN WHICH BOX IT IS

>Check the OP again.
Oops, my bad anon
I've seen the same image asking about gold.
But we agree though, and the 50/50 people are just trolling retards.
Cheers.

2/3 are breakfast naggers

box 3 is irrelevant

ball 1 and 2 are the same cases

THE PROBLEM TELL ME I PICKED A GOLDEN BALL THIS GOLDEN BALL SELECT THE BOX I AM FORCED TO USE.

WHICHEVER GOLDEN BALL I TAKE FROM THE FIRST BOX IS IRRELEVANT

IN THE SECOND STEP I AM FORCED TO TAKE THE SECOND GOLDEN BALL

IS JUST 1 CASES
BALL FROM BOX 1

THIS IS A BOX PROBLEM

>random.shuffle(random box)
YOUR CODE IS WRONG
YOU ARE PICKING FROM SAME BOX NOT A RANDOM BOX

YOU ARE NOT PICKING FROM A RANDOM BOX
YOU ARE PICKING FROM SAME BOX YOU PICKED A GOLD BALL FROM

You have to start with picking a gold ball and then picking again from same box.

You start with picking a golden ball.
YOU HAVE THIS BALL FROM THE BOX YOU PICKED FROM.
NOW WHAT ARE THE CHANCES OF THE NEXT BALL FROM THE SAME BOX BEING GOLDEN.
THE BOX ISN'T RANDOM
YOU ALRADY HAVE THE BOX THAT YOU PICKED THE FRIST GOLDEN BALL FROM.
YOU ONLY HAVE ONE BOX CHOICE AND THAT IS THE BOX YOU PICKED THE GOLD BALL FROM

Because the first pick isn't included.
You already picked the golden ball.
Its established you have a gold ball in your hand.
So, from there, what are the chances of picking another gold ball.
You are either going to pick a gold ball or silver.

The baseline is that you have a gold ball, you already picked a gold ball.
You start from having a gold ball in your hand, then picking from the same box.

how did you get a 4th box?

The box doesn't matter, what matters is how many balls are left over. Which is one ball, that could be either gold or silver.

The box doesn't matter.
You already established a box, when you picked the golden ball.

The question is predicated on everything that came before it. This is evidenced by the wording of the question.
>the next ball
Implying that we have just picked one ball out. This process of picking the ball was just described in detail, which is also modeled in my code exactly as written.
>the same box
Implying we are picking from the same box we just picked from, again which was described in detail.

What you want is to disregard the pick we just made, which is to ignore the wording of both the entire problem and the question itself, as well as just common sense and math question standards.

Instead of picking "the same box", you want to average the chance of pulling a ball out of all boxes with at least one gold ball.

It's already been established that you picked a gold ball, from a box with two balls.
Now the question starts.
What are the chances that you pick a gold ball from that SAME box.
You only have 1 ball left in the box.
Now if you have the gold ball from the g/g box, the other one is gold.
Now if you have the gold ball from the g/s box, its silver.
There are only two out comes. You don't include the first ball you picked. We already know it's a gold ball.
One is gold, one is silver.

You people really need to be more specific because it's really hard to pin down what you think my code is doing wrong and what the original question says, since your understanding of both is poor.
>Because the first pick isn't included.
I'm assuming that you mean the question is saying that the first pick isn't included, because it is certainly included in my code.
The question states:
>You pick a box at random
>You put your hand in and take a ball from that box at random
>It's a gold ball
>What is the probability that the next ball you take from the same box will be silver?
Nowhere in there does it say to discount your first pick. In fact, your first pick is integral to determining which box you just picked from, which is the major unknown, and given the fact that it says that you pick the next ball from the same box I would think it says the opposite.
What you would be looking for is a question something like this:
>What is the probability that you could pick another gold ball from a box that you can pick a gold ball from?
In contrast, the question lays out a series of steps which I follow very carefully in my code, including only counting cases where I picked a gold ball first.

You have addressed precisely none of my points, you have also produced no code. Congratulations

And again, the question very clearly lays out the steps you take to pick your box and that gold ball ball and at no point in the question do you disregard what just happened.
You are looking for this question:
>For every box which contains a gold ball, what are the chances that you could pick another gold ball out?
This would discount the first pick. Why even describe the process of making the first pick in the question?

The question is predicated on everything that came before it. This is evidenced by the wording of the question.
>the next ball
Implying that we have just picked one ball out. This process of picking the ball was just described in detail, which is also modeled in my code exactly as written.
>the same box
Implying we are picking from the same box we just picked from, again which was described in detail.

What you want is to disregard the pick we just made, which is to ignore the wording of both the entire problem and the question itself, as well as just common sense and math question standards.

Instead of picking "the same box", you want to average the chance of pulling a ball out of all boxes with at least one gold ball.

No interpretation of that statement makes sense.
I pick a random box every instance of the experiment:
>random_box = random.choice(boxes).copy()
If you mean that I'm taking the second ball out of the same box, yes, that's part of the question:
>What is the probability that the next ball you take from the SAME BOX will be silver?

The first pick parameter is unnecessary

Now show how it should work in code.

For simplicity: You never draw ball from the all silver box, that's part of the question.
So you have two boxes in front of you. Those two boxes contain 4 balls. What are your chances of picking gold vs silver? Is it 50/50?
No it's 3:1
But you already picked 1 gold, so now it's 2:1 of picking another gold.

Dude, seriously explain me how picking one ball out of the pool of four balls leaves only two balls remaining?

it depends on if you see the two gold balls in the gold box as unique objects

if you dont it is 1/2 but if you do it becomes 1/3
it would be natural to assume they are unique since in the real world they would be. but by words they are not since we havent given them unique identities yet

1/3 is right, but saying 1/2 doesnt make you a retard

>if you [don't] know know the answer simply by looking at the picture then your iq is that of a retard
You got it wrong, THOUGH

i can understand this retardism on the monty phyton problem.

but this time the answare is clear.

You only know a part of what happened in the first draw. You know that it was a gold ball but you don't know from which box it was.
That's why you calculate the probability of the two possible things that might have happened.
Look at the example in this image.

Here you can read it explained with another example next to it

It's the same thing.

SO THE NEXT ONE WILL BE A GOLDEN ONE FOR SURE SINCE BOTH BOXES HAVE 2 GOLDEN BALLS
[...]
nope
that problem consider the probability of the first pick

That post was only replying to you by accident, I meant to link the picture to the other poster I was talking to.
And yes, it's considering the probability of the first draw and that's the correct thing to do here too.

>THIS FORCE YOUR BOX TO BE THE FIRST OR THE SECOND
Yes exactly. And the probability that it was the first box is 2/3

>You only know a part of what happened in the first draw. You know that it was a gold ball but you don't know from which box it was.

Yes. But it is irrelevant. Since it doesn’t matter which of the two golden balls from box 1 you might have picked, and there being 2 golden balls in that box didn’t actually increase your chance of picking that actual box, the situation we’re actually concerned with is basically either you have a box in front of you with another gold ball in it, or a box with a silver ball in it. The question is about the boxes, not the balls.

I did read it. The first step of the setup is to chose a box, the second to choose a ball from the box. If the ball is not gold we start over, as the initial conditions were not met. Once the initial conditions are met we simply look at what other ball is still in the box, and record that as our second choice and thus the result of that iteration of the test.

You have selected a box but you don't know which box you have selected.
When you draw the gold ball, you find out that the probability that it was the first box that you selected is 2/3.

I did read it, you didn't read

The fact that it's given that you picked a gold ball doesn't tell you everything about what happened in the first draw. You know you got a gold ball but don't know which box you have chosen. Because you don't know what happened in the first draw, you look at the probabilities of what happened. Two different things can have happened, either you picked box 1 or you picked box 2, and the probability that you drew from the first box is 2/3.
The probability that you drew from the second box is 1/3.

though.
"it is hardcoded you get a gold ball." doesn't mean that you know exactly what happened in the first draw. You know that the ball was gold, but there are still two different possibilities for what happened in the first draw.

>ACCORDING TO THE PROBLEM, what are your chances at drawing a gold first from box 2?
>Hint: 100%
You don't need the if at the beginning of the question for it to be about conditional probability.

>hurrr durr
pic related, it's you

99% PROBABILITY BECAUSE I CAN CHOICE FIRST 99 DIFFERENT BALLS WHO DO NOT CHANGE THE RESULT?

IF I HAVE 99 IN THE FIRST BO OR JUST 1
THE SECOND PICKING WILL GAVE THE SAME RESULT

WHICH EVER BOX I CHOOSE